10y^2+60y+80=0

Solution for 10y^2+60y+80=0 equation:

10y^2+60y+80=0

a = 10; b = 60; c = +80;
Δ = b2-4ac
Δ = 602-4·10·80
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20}{2*10}=\frac{-80}{20}
=-4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20}{2*10}=\frac{-40}{20}
=-2
$